YES We show the termination of R/S, where R is le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(0,y) -> 0 minus(s(x),y) -> if_minus(le(s(x),y),s(x),y) if_minus(true,s(x),y) -> 0 if_minus(false,s(x),y) -> s(minus(x,y)) mod(0,y) -> 0 mod(s(x),0) -> 0 mod(s(x),s(y)) -> if_mod(le(y,x),s(x),s(y)) if_mod(true,s(x),s(y)) -> mod(minus(x,y),s(y)) if_mod(false,s(x),s(y)) -> s(x) and S is: rand(x) -> x rand(x) -> rand(s(x)) Since R almost dominates S and S is non-duplicating, it is enough to show finiteness of (P, Q). Here P consists of the dependency pairs le#(s(x),s(y)) -> le#(x,y) minus#(s(x),y) -> if_minus#(le(s(x),y),s(x),y) minus#(s(x),y) -> le#(s(x),y) if_minus#(false,s(x),y) -> minus#(x,y) mod#(s(x),s(y)) -> if_mod#(le(y,x),s(x),s(y)) mod#(s(x),s(y)) -> le#(y,x) if_mod#(true,s(x),s(y)) -> mod#(minus(x,y),s(y)) if_mod#(true,s(x),s(y)) -> minus#(x,y) and Q consists of the rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(0,y) -> 0 minus(s(x),y) -> if_minus(le(s(x),y),s(x),y) if_minus(true,s(x),y) -> 0 if_minus(false,s(x),y) -> s(minus(x,y)) mod(0,y) -> 0 mod(s(x),0) -> 0 mod(s(x),s(y)) -> if_mod(le(y,x),s(x),s(y)) if_mod(true,s(x),s(y)) -> mod(minus(x,y),s(y)) if_mod(false,s(x),s(y)) -> s(x) rand(x) -> x rand(x) -> rand(s(x)) The weakly monotone algebra (N^2, >_lex) with le#_A((x1,y1),(x2,y2)) = (0, 0) s_A((x1,y1)) = (0, 3) minus#_A((x1,y1),(x2,y2)) = (1, 1) if_minus#_A((x1,y1),(x2,y2),(x3,y3)) = (1, 1) le_A((x1,y1),(x2,y2)) = (2, 1) false_A = (1, 2) mod#_A((x1,y1),(x2,y2)) = (2, 2) if_mod#_A((x1,y1),(x2,y2),(x3,y3)) = (2, 2) true_A = (1, 2) minus_A((x1,y1),(x2,y2)) = (3, 1) 0_A = (1, 3) if_minus_A((x1,y1),(x2,y2),(x3,y3)) = (2, 2) mod_A((x1,y1),(x2,y2)) = (2, 0) if_mod_A((x1,y1),(x2,y2),(x3,y3)) = (2, 0) rand_A((x1,y1)) = (x1 + 1, 0) strictly orients the following dependency pairs: minus#(s(x),y) -> le#(s(x),y) mod#(s(x),s(y)) -> le#(y,x) if_mod#(true,s(x),s(y)) -> minus#(x,y) We remove them from the set of dependency pairs. The weakly monotone algebra (N^2, >_lex) with le#_A((x1,y1),(x2,y2)) = (x1, y1) s_A((x1,y1)) = (x1, y1 + 3) minus#_A((x1,y1),(x2,y2)) = (x1 + x2, y1 + y2 + 1) if_minus#_A((x1,y1),(x2,y2),(x3,y3)) = (x2 + x3, y2 + y3) le_A((x1,y1),(x2,y2)) = (2, 1) false_A = (1, 2) mod#_A((x1,y1),(x2,y2)) = (x1 + x2 + 2, y1 + y2 + 2) if_mod#_A((x1,y1),(x2,y2),(x3,y3)) = (x1 + x2 + x3, y1 + y2 + y3) true_A = (2, 1) minus_A((x1,y1),(x2,y2)) = (x1, y1 + 1) 0_A = (0, 0) if_minus_A((x1,y1),(x2,y2),(x3,y3)) = (x2, y2 + 1) mod_A((x1,y1),(x2,y2)) = (x1 + 1, 0) if_mod_A((x1,y1),(x2,y2),(x3,y3)) = (x2 + 1, 0) rand_A((x1,y1)) = (x1 + 1, 0) strictly orients the following dependency pairs: le#(s(x),s(y)) -> le#(x,y) minus#(s(x),y) -> if_minus#(le(s(x),y),s(x),y) if_minus#(false,s(x),y) -> minus#(x,y) mod#(s(x),s(y)) -> if_mod#(le(y,x),s(x),s(y)) if_mod#(true,s(x),s(y)) -> mod#(minus(x,y),s(y)) We remove them from the set of dependency pairs. No dependency pair remains.