NO Termination proof of rt3-6.trs

(0) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

b(a(x)) → a(b(x))

The relative TRS consists of the following S rules:

b(x) → b(b(x))
a(x) → a(a(x))

(1) RelTRSLoopFinderProof (COMPLETE transformation)

The following loop was found:

---------- Loop: ----------

b(a(x')) → b(a(a(x'))) with rule a(x'') → a(a(x'')) at position [0] and matcher [x'' / x']

b(a(a(x'))) → a(b(a(x'))) with rule b(a(x)) → a(b(x)) at position [] and matcher [x / a(x')]

Now an instance of the first term with Matcher [ ] occurs in the last term at position [0].

Context: a([])

Therefore, the relative TRS problem does not terminate.

(2) NO