NO Termination proof of rt3-3.trs

(0) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

p(0, y) → y
p(s(x), y) → s(p(x, y))

The relative TRS consists of the following S rules:

p(x, y) → s(p(x, y))

(1) RelTRSLoopFinderProof (COMPLETE transformation)

The following loop was found:

---------- Loop: ----------

p(p(x', y'), y) → p(s(p(x', y')), y) with rule p(x'', y'') → s(p(x'', y'')) at position [0] and matcher [x'' / x', y'' / y']

p(s(p(x', y')), y) → s(p(p(x', y'), y)) with rule p(s(x), y'') → s(p(x, y'')) at position [] and matcher [x / p(x', y'), y'' / y]

Now an instance of the first term with Matcher [ ] occurs in the last term at position [0].

Context: s([])

Therefore, the relative TRS problem does not terminate.

(2) NO