YES Termination proof of AG_#3.37_rand.trs

(0) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

not(true) → false
not(false) → true
evenodd(x, 0) → not(evenodd(x, s(0)))
evenodd(0, s(0)) → false
evenodd(s(x), s(0)) → evenodd(x, 0)

The relative TRS consists of the following S rules:

rand(x) → rand(s(x))
rand(x) → x

(1) RelTRSRRRProof (EQUIVALENT transformation)

We used the following monotonic ordering for rule removal:
Polynomial interpretation [POLO]:

POL(0) = 1   
POL(evenodd(x1, x2)) = 1 + x1 + x2   
POL(false) = 0   
POL(not(x1)) = x1   
POL(rand(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(true) = 0   
With this ordering the following rules can be removed [MATRO] because they are oriented strictly:
Rules from R:

evenodd(0, s(0)) → false
Rules from S:

rand(x) → x


(2) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

not(true) → false
not(false) → true
evenodd(x, 0) → not(evenodd(x, s(0)))
evenodd(s(x), s(0)) → evenodd(x, 0)

The relative TRS consists of the following S rules:

rand(x) → rand(s(x))

(3) RelTRSRRRProof (EQUIVALENT transformation)

We used the following monotonic ordering for rule removal:
Matrix interpretation [MATRO] to (N^2, +, *, >=, >) :

POL(not(x1)) =
/0\
\0/
+
/11\
\01/
·x1

POL(true) =
/0\
\1/

POL(false) =
/1\
\1/

POL(evenodd(x1, x2)) =
/0\
\0/
+
/10\
\00/
·x1 +
/10\
\00/
·x2

POL(0) =
/0\
\0/

POL(s(x1)) =
/0\
\0/
+
/10\
\01/
·x1

POL(rand(x1)) =
/1\
\1/
+
/10\
\00/
·x1
With this ordering the following rules can be removed [MATRO] because they are oriented strictly:
Rules from R:

not(false) → true
Rules from S:
none


(4) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

not(true) → false
evenodd(x, 0) → not(evenodd(x, s(0)))
evenodd(s(x), s(0)) → evenodd(x, 0)

The relative TRS consists of the following S rules:

rand(x) → rand(s(x))

(5) RelTRSRRRProof (EQUIVALENT transformation)

We used the following monotonic ordering for rule removal:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(evenodd(x1, x2)) = x1 + x2   
POL(false) = 0   
POL(not(x1)) = x1   
POL(rand(x1)) = x1   
POL(s(x1)) = x1   
POL(true) = 1   
With this ordering the following rules can be removed [MATRO] because they are oriented strictly:
Rules from R:

not(true) → false
Rules from S:
none


(6) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

evenodd(x, 0) → not(evenodd(x, s(0)))
evenodd(s(x), s(0)) → evenodd(x, 0)

The relative TRS consists of the following S rules:

rand(x) → rand(s(x))

(7) RelTRSRRRProof (EQUIVALENT transformation)

We used the following monotonic ordering for rule removal:
Matrix interpretation [MATRO] to (N^2, +, *, >=, >) :

POL(evenodd(x1, x2)) =
/0\
\0/
+
/11\
\00/
·x1 +
/10\
\00/
·x2

POL(0) =
/0\
\1/

POL(not(x1)) =
/0\
\0/
+
/11\
\00/
·x1

POL(s(x1)) =
/0\
\1/
+
/10\
\01/
·x1

POL(rand(x1)) =
/1\
\1/
+
/10\
\00/
·x1
With this ordering the following rules can be removed [MATRO] because they are oriented strictly:
Rules from R:

evenodd(s(x), s(0)) → evenodd(x, 0)
Rules from S:
none


(8) Obligation:

Relative term rewrite system:
The relative TRS consists of the following R rules:

evenodd(x, 0) → not(evenodd(x, s(0)))

The relative TRS consists of the following S rules:

rand(x) → rand(s(x))

(9) RelTRSRRRProof (EQUIVALENT transformation)

We used the following monotonic ordering for rule removal:
Matrix interpretation [MATRO] to (N^2, +, *, >=, >) :

POL(evenodd(x1, x2)) =
/0\
\0/
+
/10\
\00/
·x1 +
/11\
\00/
·x2

POL(0) =
/0\
\1/

POL(not(x1)) =
/0\
\0/
+
/11\
\00/
·x1

POL(s(x1)) =
/0\
\0/
+
/10\
\00/
·x1

POL(rand(x1)) =
/1\
\1/
+
/10\
\00/
·x1
With this ordering the following rules can be removed [MATRO] because they are oriented strictly:
Rules from R:

evenodd(x, 0) → not(evenodd(x, s(0)))
Rules from S:
none


(10) Obligation:

Relative term rewrite system:
R is empty.
The relative TRS consists of the following S rules:

rand(x) → rand(s(x))

(11) RIsEmptyProof (EQUIVALENT transformation)

The TRS R is empty. Hence, termination is trivially proven.

(12) YES