YES

We show the termination of the TRS R:

  a(b(a(x))) -> b(a(x))

-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

  (no rules)

and R consists of:

r1: a(b(a(x))) -> b(a(x))

The estimated dependency graph contains the following SCCs:

  (no SCCs)