YES

We show the termination of the TRS R:

  __(__(X,Y),Z) -> __(X,__(Y,Z))
  __(X,nil()) -> X
  __(nil(),X) -> X
  and(tt(),X) -> activate(X)
  isList(V) -> isNeList(activate(V))
  isList(n__nil()) -> tt()
  isList(n____(V1,V2)) -> and(isList(activate(V1)),n__isList(activate(V2)))
  isNeList(V) -> isQid(activate(V))
  isNeList(n____(V1,V2)) -> and(isList(activate(V1)),n__isNeList(activate(V2)))
  isNeList(n____(V1,V2)) -> and(isNeList(activate(V1)),n__isList(activate(V2)))
  isNePal(V) -> isQid(activate(V))
  isNePal(n____(I,__(P,I))) -> and(isQid(activate(I)),n__isPal(activate(P)))
  isPal(V) -> isNePal(activate(V))
  isPal(n__nil()) -> tt()
  isQid(n__a()) -> tt()
  isQid(n__e()) -> tt()
  isQid(n__i()) -> tt()
  isQid(n__o()) -> tt()
  isQid(n__u()) -> tt()
  nil() -> n__nil()
  __(X1,X2) -> n____(X1,X2)
  isList(X) -> n__isList(X)
  isNeList(X) -> n__isNeList(X)
  isPal(X) -> n__isPal(X)
  a() -> n__a()
  e() -> n__e()
  i() -> n__i()
  o() -> n__o()
  u() -> n__u()
  activate(n__nil()) -> nil()
  activate(n____(X1,X2)) -> __(X1,X2)
  activate(n__isList(X)) -> isList(X)
  activate(n__isNeList(X)) -> isNeList(X)
  activate(n__isPal(X)) -> isPal(X)
  activate(n__a()) -> a()
  activate(n__e()) -> e()
  activate(n__i()) -> i()
  activate(n__o()) -> o()
  activate(n__u()) -> u()
  activate(X) -> X

-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: __#(__(X,Y),Z) -> __#(X,__(Y,Z))
p2: __#(__(X,Y),Z) -> __#(Y,Z)
p3: and#(tt(),X) -> activate#(X)
p4: isList#(V) -> isNeList#(activate(V))
p5: isList#(V) -> activate#(V)
p6: isList#(n____(V1,V2)) -> and#(isList(activate(V1)),n__isList(activate(V2)))
p7: isList#(n____(V1,V2)) -> isList#(activate(V1))
p8: isList#(n____(V1,V2)) -> activate#(V1)
p9: isList#(n____(V1,V2)) -> activate#(V2)
p10: isNeList#(V) -> isQid#(activate(V))
p11: isNeList#(V) -> activate#(V)
p12: isNeList#(n____(V1,V2)) -> and#(isList(activate(V1)),n__isNeList(activate(V2)))
p13: isNeList#(n____(V1,V2)) -> isList#(activate(V1))
p14: isNeList#(n____(V1,V2)) -> activate#(V1)
p15: isNeList#(n____(V1,V2)) -> activate#(V2)
p16: isNeList#(n____(V1,V2)) -> and#(isNeList(activate(V1)),n__isList(activate(V2)))
p17: isNeList#(n____(V1,V2)) -> isNeList#(activate(V1))
p18: isNeList#(n____(V1,V2)) -> activate#(V1)
p19: isNeList#(n____(V1,V2)) -> activate#(V2)
p20: isNePal#(V) -> isQid#(activate(V))
p21: isNePal#(V) -> activate#(V)
p22: isNePal#(n____(I,__(P,I))) -> and#(isQid(activate(I)),n__isPal(activate(P)))
p23: isNePal#(n____(I,__(P,I))) -> isQid#(activate(I))
p24: isNePal#(n____(I,__(P,I))) -> activate#(I)
p25: isNePal#(n____(I,__(P,I))) -> activate#(P)
p26: isPal#(V) -> isNePal#(activate(V))
p27: isPal#(V) -> activate#(V)
p28: activate#(n__nil()) -> nil#()
p29: activate#(n____(X1,X2)) -> __#(X1,X2)
p30: activate#(n__isList(X)) -> isList#(X)
p31: activate#(n__isNeList(X)) -> isNeList#(X)
p32: activate#(n__isPal(X)) -> isPal#(X)
p33: activate#(n__a()) -> a#()
p34: activate#(n__e()) -> e#()
p35: activate#(n__i()) -> i#()
p36: activate#(n__o()) -> o#()
p37: activate#(n__u()) -> u#()

and R consists of:

r1: __(__(X,Y),Z) -> __(X,__(Y,Z))
r2: __(X,nil()) -> X
r3: __(nil(),X) -> X
r4: and(tt(),X) -> activate(X)
r5: isList(V) -> isNeList(activate(V))
r6: isList(n__nil()) -> tt()
r7: isList(n____(V1,V2)) -> and(isList(activate(V1)),n__isList(activate(V2)))
r8: isNeList(V) -> isQid(activate(V))
r9: isNeList(n____(V1,V2)) -> and(isList(activate(V1)),n__isNeList(activate(V2)))
r10: isNeList(n____(V1,V2)) -> and(isNeList(activate(V1)),n__isList(activate(V2)))
r11: isNePal(V) -> isQid(activate(V))
r12: isNePal(n____(I,__(P,I))) -> and(isQid(activate(I)),n__isPal(activate(P)))
r13: isPal(V) -> isNePal(activate(V))
r14: isPal(n__nil()) -> tt()
r15: isQid(n__a()) -> tt()
r16: isQid(n__e()) -> tt()
r17: isQid(n__i()) -> tt()
r18: isQid(n__o()) -> tt()
r19: isQid(n__u()) -> tt()
r20: nil() -> n__nil()
r21: __(X1,X2) -> n____(X1,X2)
r22: isList(X) -> n__isList(X)
r23: isNeList(X) -> n__isNeList(X)
r24: isPal(X) -> n__isPal(X)
r25: a() -> n__a()
r26: e() -> n__e()
r27: i() -> n__i()
r28: o() -> n__o()
r29: u() -> n__u()
r30: activate(n__nil()) -> nil()
r31: activate(n____(X1,X2)) -> __(X1,X2)
r32: activate(n__isList(X)) -> isList(X)
r33: activate(n__isNeList(X)) -> isNeList(X)
r34: activate(n__isPal(X)) -> isPal(X)
r35: activate(n__a()) -> a()
r36: activate(n__e()) -> e()
r37: activate(n__i()) -> i()
r38: activate(n__o()) -> o()
r39: activate(n__u()) -> u()
r40: activate(X) -> X

The estimated dependency graph contains the following SCCs:

  {p3, p4, p5, p6, p7, p8, p9, p11, p12, p13, p14, p15, p16, p17, p18, p19, p21, p22, p24, p25, p26, p27, p30, p31, p32}
  {p1, p2}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: isPal#(V) -> activate#(V)
p2: activate#(n__isPal(X)) -> isPal#(X)
p3: isPal#(V) -> isNePal#(activate(V))
p4: isNePal#(n____(I,__(P,I))) -> activate#(P)
p5: activate#(n__isNeList(X)) -> isNeList#(X)
p6: isNeList#(n____(V1,V2)) -> activate#(V2)
p7: activate#(n__isList(X)) -> isList#(X)
p8: isList#(n____(V1,V2)) -> activate#(V2)
p9: isList#(n____(V1,V2)) -> activate#(V1)
p10: isList#(n____(V1,V2)) -> isList#(activate(V1))
p11: isList#(n____(V1,V2)) -> and#(isList(activate(V1)),n__isList(activate(V2)))
p12: and#(tt(),X) -> activate#(X)
p13: isList#(V) -> activate#(V)
p14: isList#(V) -> isNeList#(activate(V))
p15: isNeList#(n____(V1,V2)) -> activate#(V1)
p16: isNeList#(n____(V1,V2)) -> isNeList#(activate(V1))
p17: isNeList#(n____(V1,V2)) -> and#(isNeList(activate(V1)),n__isList(activate(V2)))
p18: isNeList#(n____(V1,V2)) -> isList#(activate(V1))
p19: isNeList#(n____(V1,V2)) -> and#(isList(activate(V1)),n__isNeList(activate(V2)))
p20: isNeList#(V) -> activate#(V)
p21: isNePal#(n____(I,__(P,I))) -> activate#(I)
p22: isNePal#(n____(I,__(P,I))) -> and#(isQid(activate(I)),n__isPal(activate(P)))
p23: isNePal#(V) -> activate#(V)

and R consists of:

r1: __(__(X,Y),Z) -> __(X,__(Y,Z))
r2: __(X,nil()) -> X
r3: __(nil(),X) -> X
r4: and(tt(),X) -> activate(X)
r5: isList(V) -> isNeList(activate(V))
r6: isList(n__nil()) -> tt()
r7: isList(n____(V1,V2)) -> and(isList(activate(V1)),n__isList(activate(V2)))
r8: isNeList(V) -> isQid(activate(V))
r9: isNeList(n____(V1,V2)) -> and(isList(activate(V1)),n__isNeList(activate(V2)))
r10: isNeList(n____(V1,V2)) -> and(isNeList(activate(V1)),n__isList(activate(V2)))
r11: isNePal(V) -> isQid(activate(V))
r12: isNePal(n____(I,__(P,I))) -> and(isQid(activate(I)),n__isPal(activate(P)))
r13: isPal(V) -> isNePal(activate(V))
r14: isPal(n__nil()) -> tt()
r15: isQid(n__a()) -> tt()
r16: isQid(n__e()) -> tt()
r17: isQid(n__i()) -> tt()
r18: isQid(n__o()) -> tt()
r19: isQid(n__u()) -> tt()
r20: nil() -> n__nil()
r21: __(X1,X2) -> n____(X1,X2)
r22: isList(X) -> n__isList(X)
r23: isNeList(X) -> n__isNeList(X)
r24: isPal(X) -> n__isPal(X)
r25: a() -> n__a()
r26: e() -> n__e()
r27: i() -> n__i()
r28: o() -> n__o()
r29: u() -> n__u()
r30: activate(n__nil()) -> nil()
r31: activate(n____(X1,X2)) -> __(X1,X2)
r32: activate(n__isList(X)) -> isList(X)
r33: activate(n__isNeList(X)) -> isNeList(X)
r34: activate(n__isPal(X)) -> isPal(X)
r35: activate(n__a()) -> a()
r36: activate(n__e()) -> e()
r37: activate(n__i()) -> i()
r38: activate(n__o()) -> o()
r39: activate(n__u()) -> u()
r40: activate(X) -> X

The set of usable rules consists of

  r1, r2, r3, r4, r5, r6, r7, r8, r9, r10, r11, r12, r13, r14, r15, r16, r17, r18, r19, r20, r21, r22, r23, r24, r25, r26, r27, r28, r29, r30, r31, r32, r33, r34, r35, r36, r37, r38, r39, r40

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. matrix interpretations:
    
      carrier: N^1
      order: standard order
      interpretations:
        isPal#_A(x1) = x1 + 4
        activate#_A(x1) = x1
        n__isPal_A(x1) = x1 + 5
        isNePal#_A(x1) = x1 + 1
        activate_A(x1) = x1 + 2
        n_____A(x1,x2) = x1 + x2 + 13
        ___A(x1,x2) = x1 + x2 + 14
        n__isNeList_A(x1) = x1 + 2
        isNeList#_A(x1) = x1 + 1
        n__isList_A(x1) = x1 + 5
        isList#_A(x1) = x1 + 4
        and#_A(x1,x2) = x1 + x2 + 1
        isList_A(x1) = x1 + 6
        tt_A() = 0
        isNeList_A(x1) = x1 + 3
        isQid_A(x1) = 0
        isNePal_A(x1) = x1 + 1
        and_A(x1,x2) = x1 + x2 + 3
        nil_A() = 2
        isPal_A(x1) = x1 + 6
        n__nil_A() = 1
        a_A() = 2
        n__a_A() = 1
        e_A() = 2
        n__e_A() = 1
        i_A() = 2
        n__i_A() = 1
        o_A() = 2
        n__o_A() = 1
        u_A() = 2
        n__u_A() = 1
    
    2. lexicographic path order with precedence:
    
      precedence:
      
        u > n__u > n__o > o > n__i > i > n__e > e > n__a > a > n__nil > isNePal > isPal > nil > __ > and > isQid > tt > n__isList > isNeList > n____ > isList# > isList > activate# > and# > n__isNeList > activate > isNeList# > isPal# > n__isPal > isNePal#
      
      argument filter:
    
        pi(isPal#) = [1]
        pi(activate#) = [1]
        pi(n__isPal) = 1
        pi(isNePal#) = []
        pi(activate) = []
        pi(n____) = [1, 2]
        pi(__) = 1
        pi(n__isNeList) = 1
        pi(isNeList#) = [1]
        pi(n__isList) = [1]
        pi(isList#) = []
        pi(and#) = []
        pi(isList) = []
        pi(tt) = []
        pi(isNeList) = 1
        pi(isQid) = []
        pi(isNePal) = [1]
        pi(and) = 1
        pi(nil) = []
        pi(isPal) = 1
        pi(n__nil) = []
        pi(a) = []
        pi(n__a) = []
        pi(e) = []
        pi(n__e) = []
        pi(i) = []
        pi(n__i) = []
        pi(o) = []
        pi(n__o) = []
        pi(u) = []
        pi(n__u) = []
    

The next rules are strictly ordered:

  p1, p2, p3, p4, p5, p6, p7, p8, p9, p10, p11, p12, p13, p14, p15, p16, p17, p18, p19, p20, p21, p22, p23

We remove them from the problem.  Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: __#(__(X,Y),Z) -> __#(X,__(Y,Z))
p2: __#(__(X,Y),Z) -> __#(Y,Z)

and R consists of:

r1: __(__(X,Y),Z) -> __(X,__(Y,Z))
r2: __(X,nil()) -> X
r3: __(nil(),X) -> X
r4: and(tt(),X) -> activate(X)
r5: isList(V) -> isNeList(activate(V))
r6: isList(n__nil()) -> tt()
r7: isList(n____(V1,V2)) -> and(isList(activate(V1)),n__isList(activate(V2)))
r8: isNeList(V) -> isQid(activate(V))
r9: isNeList(n____(V1,V2)) -> and(isList(activate(V1)),n__isNeList(activate(V2)))
r10: isNeList(n____(V1,V2)) -> and(isNeList(activate(V1)),n__isList(activate(V2)))
r11: isNePal(V) -> isQid(activate(V))
r12: isNePal(n____(I,__(P,I))) -> and(isQid(activate(I)),n__isPal(activate(P)))
r13: isPal(V) -> isNePal(activate(V))
r14: isPal(n__nil()) -> tt()
r15: isQid(n__a()) -> tt()
r16: isQid(n__e()) -> tt()
r17: isQid(n__i()) -> tt()
r18: isQid(n__o()) -> tt()
r19: isQid(n__u()) -> tt()
r20: nil() -> n__nil()
r21: __(X1,X2) -> n____(X1,X2)
r22: isList(X) -> n__isList(X)
r23: isNeList(X) -> n__isNeList(X)
r24: isPal(X) -> n__isPal(X)
r25: a() -> n__a()
r26: e() -> n__e()
r27: i() -> n__i()
r28: o() -> n__o()
r29: u() -> n__u()
r30: activate(n__nil()) -> nil()
r31: activate(n____(X1,X2)) -> __(X1,X2)
r32: activate(n__isList(X)) -> isList(X)
r33: activate(n__isNeList(X)) -> isNeList(X)
r34: activate(n__isPal(X)) -> isPal(X)
r35: activate(n__a()) -> a()
r36: activate(n__e()) -> e()
r37: activate(n__i()) -> i()
r38: activate(n__o()) -> o()
r39: activate(n__u()) -> u()
r40: activate(X) -> X

The set of usable rules consists of

  r1, r2, r3, r21

Take the reduction pair:

  lexicographic combination of reduction pairs:
  
    1. matrix interpretations:
    
      carrier: N^1
      order: standard order
      interpretations:
        __#_A(x1,x2) = x1
        ___A(x1,x2) = x1 + x2 + 1
        nil_A() = 0
        n_____A(x1,x2) = x2
    
    2. lexicographic path order with precedence:
    
      precedence:
      
        n____ > nil > __ > __#
      
      argument filter:
    
        pi(__#) = 1
        pi(__) = 2
        pi(nil) = []
        pi(n____) = 2
    

The next rules are strictly ordered:

  p1, p2

We remove them from the problem.  Then no dependency pair remains.