YES Termination w.r.t. Q proof of Zantema_05_z03.ari

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(f, a(g, a(f, x))) → a(f, a(g, a(g, a(f, x))))
a(g, a(f, a(g, x))) → a(g, a(f, a(f, a(g, x))))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(f, a(g, a(f, x))) → A(f, a(g, a(g, a(f, x))))
A(f, a(g, a(f, x))) → A(g, a(g, a(f, x)))
A(g, a(f, a(g, x))) → A(g, a(f, a(f, a(g, x))))
A(g, a(f, a(g, x))) → A(f, a(f, a(g, x)))

The TRS R consists of the following rules:

a(f, a(g, a(f, x))) → a(f, a(g, a(g, a(f, x))))
a(g, a(f, a(g, x))) → a(g, a(f, a(f, a(g, x))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) UsableRulesReductionPairsProof (EQUIVALENT transformation)

First, we A-transformed [FROCOS05] the QDP-Problem. Then we obtain the following A-transformed DP problem.
The pairs P are:

f1(g(f(x))) → f1(g(g(f(x))))
f1(g(f(x))) → g1(g(f(x)))
g1(f(g(x))) → g1(f(f(g(x))))
g1(f(g(x))) → f1(f(g(x)))

and the Q and R are:
Q restricted rewrite system:
The TRS R consists of the following rules:

g(f(g(x))) → g(f(f(g(x))))
f(g(f(x))) → f(g(g(f(x))))

Q is empty.

By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

No dependency pairs are removed.

The following rules are removed from R:

a(f, a(g, a(f, x))) → a(f, a(g, a(g, a(f, x))))
a(g, a(f, a(g, x))) → a(g, a(f, a(f, a(g, x))))
Used ordering: POLO with Polynomial interpretation [POLO]:

POL(f(x1)) = x1   
POL(f1(x1)) = 2 + x1   
POL(g(x1)) = x1   
POL(g1(x1)) = 2 + x1   

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

f1(g(f(x))) → f1(g(g(f(x))))
f1(g(f(x))) → g1(g(f(x)))
g1(f(g(x))) → g1(f(f(g(x))))
g1(f(g(x))) → f1(f(g(x)))

The TRS R consists of the following rules:

g(f(g(x))) → g(f(f(g(x))))
f(g(f(x))) → f(g(g(f(x))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) RFCMatchBoundsDPProof (EQUIVALENT transformation)

Finiteness of the DP problem can be shown by a matchbound of 2.
As the DP problem is minimal we only have to initialize the certificate graph by the rules of P:

f1(g(f(x))) → f1(g(g(f(x))))
f1(g(f(x))) → g1(g(f(x)))
g1(f(g(x))) → g1(f(f(g(x))))
g1(f(g(x))) → f1(f(g(x)))

To find matches we regarded all rules of R and P:

g(f(g(x))) → g(f(f(g(x))))
f(g(f(x))) → f(g(g(f(x))))
f1(g(f(x))) → f1(g(g(f(x))))
f1(g(f(x))) → g1(g(f(x)))
g1(f(g(x))) → g1(f(f(g(x))))
g1(f(g(x))) → f1(f(g(x)))

The certificate found is represented by the following graph.

The certificate consists of the following enumerated nodes:

40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59

Node 40 is start node and node 41 is final node.

Those nodes are connected through the following edges:

  • 40 to 42 labelled f1_1(0)
  • 40 to 43 labelled g1_1(0)
  • 40 to 45 labelled g1_1(0)
  • 40 to 46 labelled f1_1(0)
  • 41 to 41 labelled #_1(0)
  • 42 to 43 labelled g_1(0)
  • 43 to 44 labelled g_1(0)
  • 43 to 51 labelled g_1(1)
  • 44 to 41 labelled f_1(0)
  • 44 to 48 labelled f_1(1)
  • 45 to 46 labelled f_1(0)
  • 46 to 47 labelled f_1(0)
  • 46 to 48 labelled f_1(1)
  • 47 to 41 labelled g_1(0)
  • 47 to 51 labelled g_1(1)
  • 48 to 49 labelled g_1(1)
  • 49 to 50 labelled g_1(1)
  • 49 to 51 labelled g_1(1)
  • 49 to 54 labelled g_1(2)
  • 50 to 41 labelled f_1(1)
  • 50 to 48 labelled f_1(1)
  • 51 to 52 labelled f_1(1)
  • 52 to 53 labelled f_1(1)
  • 52 to 48 labelled f_1(1)
  • 52 to 57 labelled f_1(2)
  • 53 to 41 labelled g_1(1)
  • 53 to 51 labelled g_1(1)
  • 54 to 55 labelled f_1(2)
  • 55 to 56 labelled f_1(2)
  • 56 to 49 labelled g_1(2)
  • 57 to 58 labelled g_1(2)
  • 58 to 59 labelled g_1(2)
  • 59 to 52 labelled f_1(2)

(6) YES