0 QTRS
↳1 QTRS Reverse (⇔, 0 ms)
↳2 QTRS
↳3 RFCMatchBoundsTRSProof (⇔, 0 ms)
↳4 YES
a__c → a__f(g(c))
a__f(g(X)) → g(X)
mark(c) → a__c
mark(f(X)) → a__f(X)
mark(g(X)) → g(X)
a__c → c
a__f(X) → f(X)
a__c'(x) → c'(g(a__f(x)))
g(a__f(X)) → g(X)
c'(mark(x)) → a__c'(x)
f(mark(X)) → a__f(X)
g(mark(X)) → g(X)
a__c'(x) → c'(x)
a__f(X) → f(X)
a__c'(x) → c'(g(a__f(x)))
g(a__f(X)) → g(X)
c'(mark(x)) → a__c'(x)
f(mark(X)) → a__f(X)
g(mark(X)) → g(X)
a__c'(x) → c'(x)
a__f(X) → f(X)
The certificate consists of the following enumerated nodes:
2, 4, 7, 8, 9, 10, 13, 14
Node 2 is start node and node 4 is final node.
Those nodes are connected through the following edges: