YES
0 QTRS
↳1 QTRS Reverse (⇔, 0 ms)
↳2 QTRS
↳3 RFCMatchBoundsTRSProof (⇔, 0 ms)
↳4 YES
a__f(f(a)) → c(f(g(f(a))))
mark(f(X)) → a__f(mark(X))
mark(a) → a
mark(c(X)) → c(X)
mark(g(X)) → g(mark(X))
a__f(X) → f(X)
a'(f(a__f(x))) → a'(f(g(f(c(x)))))
f(mark(X)) → mark(a__f(X))
a'(mark(x)) → a'(x)
c(mark(X)) → c(X)
g(mark(X)) → mark(g(X))
a__f(X) → f(X)
a'(f(a__f(x))) → a'(f(g(f(c(x)))))
f(mark(X)) → mark(a__f(X))
a'(mark(x)) → a'(x)
c(mark(X)) → c(X)
g(mark(X)) → mark(g(X))
a__f(X) → f(X)
The certificate consists of the following enumerated nodes:
1, 4, 5, 7, 8, 9, 10, 16, 17, 18, 19, 20, 21
Node 1 is start node and node 4 is final node.
Those nodes are connected through the following edges: