YES
0 QTRS
↳1 RFCMatchBoundsTRSProof (⇔, 0 ms)
↳2 YES
f(h(x)) → f(i(x))
g(i(x)) → g(h(x))
h(a) → b
i(a) → b
f(h(x)) → f(i(x))
g(i(x)) → g(h(x))
h(a) → b
i(a) → b
The certificate consists of the following enumerated nodes:
2, 4, 5, 8
Node 2 is start node and node 4 is final node.
Those nodes are connected through the following edges: