YES Termination w.r.t. Q proof of Mixed_TRS_test1.ari

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(s(x), y) → f(x, s(s(x)))
f(x, s(s(y))) → f(y, x)

Q is empty.

(1) AAECC Innermost (EQUIVALENT transformation)

We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is none

The TRS R 2 is

f(s(x), y) → f(x, s(s(x)))
f(x, s(s(y))) → f(y, x)

The signature Sigma is {f}

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(s(x), y) → f(x, s(s(x)))
f(x, s(s(y))) → f(y, x)

The set Q consists of the following terms:

f(s(x0), x1)
f(x0, s(s(x1)))

(3) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(s(x), y) → F(x, s(s(x)))
F(x, s(s(y))) → F(y, x)

The TRS R consists of the following rules:

f(s(x), y) → f(x, s(s(x)))
f(x, s(s(y))) → f(y, x)

The set Q consists of the following terms:

f(s(x0), x1)
f(x0, s(s(x1)))

We have to consider all minimal (P,Q,R)-chains.

(5) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(s(x), y) → F(x, s(s(x)))
F(x, s(s(y))) → F(y, x)

R is empty.
The set Q consists of the following terms:

f(s(x0), x1)
f(x0, s(s(x1)))

We have to consider all minimal (P,Q,R)-chains.

(7) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f(s(x0), x1)
f(x0, s(s(x1)))

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(s(x), y) → F(x, s(s(x)))
F(x, s(s(y))) → F(y, x)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


F(x, s(s(y))) → F(y, x)
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(F(x1, x2)) = 0A + 4A·x1 + 0A·x2

POL(s(x1)) = 0A + 4A·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:
none

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(s(x), y) → F(x, s(s(x)))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • F(s(x), y) → F(x, s(s(x)))
    The graph contains the following edges 1 > 1

(12) YES