NO
by csi
The rewrite relation of the following TRS is considered.
a(x) | → | b(x) |
b(b(c(x))) | → | c(a(c(a(a(x))))) |
c(c(x)) | → | x |
t0 | = | b(b(c(c(x109)))) |
→1.1 | b(b(x109)) | |
= | t1 |
t0 | = | b(b(c(c(x109)))) |
→ε | c(a(c(a(a(c(x109)))))) | |
→1.1.1.1 | c(a(c(a(b(c(x109)))))) | |
→1.1.1 | c(a(c(b(b(c(x109)))))) | |
→1 | c(b(c(b(b(c(x109)))))) | |
→1.1.1 | c(b(c(c(a(c(a(a(x109)))))))) | |
→1.1.1.1.1.1.1 | c(b(c(c(a(c(a(b(x109)))))))) | |
→1.1.1.1.1.1 | c(b(c(c(a(c(b(b(x109)))))))) | |
→1.1.1.1 | c(b(c(c(b(c(b(b(x109)))))))) | |
→1.1 | c(b(b(c(b(b(x109)))))) | |
→1 | c(c(a(c(a(a(b(b(x109)))))))) | |
→1.1.1.1.1 | c(c(a(c(a(b(b(b(x109)))))))) | |
→1.1.1.1 | c(c(a(c(b(b(b(b(x109)))))))) | |
→1.1 | c(c(b(c(b(b(b(b(x109)))))))) | |
→ε | b(c(b(b(b(b(x109)))))) | |
= | t14 |
csi