NO
by csi
The rewrite relation of the following TRS is considered.
0(2(1(x))) | → | 0(4(0(1(4(5(1(5(0(1(x)))))))))) |
1(1(3(x))) | → | 1(2(1(2(2(2(5(1(4(2(x)))))))))) |
0(0(0(3(x)))) | → | 4(2(4(0(2(5(3(3(4(5(x)))))))))) |
1(0(2(3(x)))) | → | 1(1(2(5(4(1(2(4(3(2(x)))))))))) |
1(3(5(3(x)))) | → | 3(5(4(5(2(4(3(2(5(4(x)))))))))) |
0(2(3(1(3(x))))) | → | 1(0(1(2(1(3(1(3(1(2(x)))))))))) |
0(3(4(5(3(x))))) | → | 2(0(2(5(1(2(4(4(5(5(x)))))))))) |
0(5(2(1(3(x))))) | → | 2(4(2(5(2(4(3(0(2(4(x)))))))))) |
2(1(3(1(0(x))))) | → | 0(1(4(5(1(5(5(2(3(0(x)))))))))) |
0(5(2(2(2(0(x)))))) | → | 2(5(4(3(0(2(5(1(2(1(x)))))))))) |
2(0(0(5(2(0(x)))))) | → | 4(0(4(2(1(4(4(4(0(1(x)))))))))) |
2(0(5(3(0(2(x)))))) | → | 2(5(3(5(1(4(5(0(0(2(x)))))))))) |
2(1(0(2(1(5(x)))))) | → | 2(5(4(1(3(2(2(5(4(5(x)))))))))) |
5(1(5(1(0(2(x)))))) | → | 4(5(0(0(4(3(1(1(0(4(x)))))))))) |
0(5(2(2(2(1(0(x))))))) | → | 0(3(2(3(1(4(1(0(1(0(x)))))))))) |
0(5(3(5(3(1(5(x))))))) | → | 0(1(3(4(0(1(4(5(1(5(x)))))))))) |
1(1(5(1(4(4(3(x))))))) | → | 1(0(3(4(4(1(0(2(5(5(x)))))))))) |
1(3(2(3(0(5(3(x))))))) | → | 1(4(0(1(5(4(0(3(2(5(x)))))))))) |
1(5(2(4(2(1(1(x))))))) | → | 4(4(1(4(1(4(3(1(0(3(x)))))))))) |
2(0(2(0(2(1(0(x))))))) | → | 2(0(2(3(4(2(4(4(4(0(x)))))))))) |
2(4(5(5(1(3(5(x))))))) | → | 2(1(2(1(4(4(4(3(4(4(x)))))))))) |
3(0(0(5(5(2(1(x))))))) | → | 0(2(4(3(2(3(2(1(0(3(x)))))))))) |
3(1(5(2(3(0(5(x))))))) | → | 5(3(4(0(4(5(2(0(0(4(x)))))))))) |
t0 | = | 2(0(5(3(0(2(1(x3017))))))) |
→1.1.1.1 | 2(0(5(3(0(4(0(1(4(5(1(5(0(1(x3017)))))))))))))) | |
= | t1 |
t0 | = | 2(0(5(3(0(2(1(x3017))))))) |
→ε | 2(5(3(5(1(4(5(0(0(2(1(x3017))))))))))) | |
= | t1 |
csi