NO
by csi
The rewrite relation of the following TRS is considered.
5(5(x)) | → | 0(5(4(0(2(5(4(5(2(1(x)))))))))) |
5(5(x)) | → | 3(4(1(1(1(1(4(4(0(4(x)))))))))) |
2(5(5(x))) | → | 4(2(5(4(4(0(0(1(1(2(x)))))))))) |
5(2(4(x))) | → | 0(5(0(2(3(3(4(2(4(2(x)))))))))) |
5(5(2(x))) | → | 0(1(3(2(3(0(3(2(5(3(x)))))))))) |
5(5(3(x))) | → | 0(3(5(4(4(1(0(1(5(0(x)))))))))) |
5(5(5(x))) | → | 5(3(4(1(0(1(4(5(0(0(x)))))))))) |
2(5(0(4(x)))) | → | 4(4(3(2(4(4(5(1(0(0(x)))))))))) |
4(5(2(4(x)))) | → | 4(1(5(5(2(0(3(1(3(3(x)))))))))) |
4(5(5(5(x)))) | → | 1(5(1(2(0(3(2(1(0(5(x)))))))))) |
0(2(5(3(4(x))))) | → | 3(2(4(3(1(5(1(1(3(4(x)))))))))) |
2(5(5(3(4(x))))) | → | 4(5(4(3(1(4(0(2(4(4(x)))))))))) |
5(5(5(1(4(x))))) | → | 3(3(0(5(0(4(3(4(4(0(x)))))))))) |
0(4(4(5(5(5(x)))))) | → | 0(4(4(4(3(3(4(1(3(1(x)))))))))) |
1(2(4(5(2(4(x)))))) | → | 3(3(5(3(0(4(0(3(1(3(x)))))))))) |
4(1(5(5(0(4(x)))))) | → | 1(0(3(0(4(2(4(4(3(4(x)))))))))) |
4(2(5(5(1(5(x)))))) | → | 2(3(4(2(1(1(3(4(2(5(x)))))))))) |
5(2(5(5(0(4(x)))))) | → | 0(4(2(3(3(5(2(1(4(4(x)))))))))) |
5(5(2(4(5(0(x)))))) | → | 2(1(1(4(2(4(0(4(2(0(x)))))))))) |
0(1(5(5(5(3(5(x))))))) | → | 5(3(2(5(1(0(1(2(0(5(x)))))))))) |
4(4(5(2(4(2(2(x))))))) | → | 4(0(5(5(4(5(1(2(2(1(x)))))))))) |
t0 | = | 5(5(5(x2017))) |
→1 | 5(0(5(4(0(2(5(4(5(2(1(x2017))))))))))) | |
= | t1 |
t0 | = | 5(5(5(x2017))) |
→ε | 0(5(4(0(2(5(4(5(2(1(5(x2017))))))))))) | |
= | t1 |
csi