NO
by csi
The rewrite relation of the following TRS is considered.
a(b(x)) | → | b(c(x)) |
a(c(x)) | → | c(a(x)) |
b(b(x)) | → | a(c(x)) |
c(b(x)) | → | b(c(x)) |
c(b(x)) | → | c(c(x)) |
c(c(x)) | → | c(b(x)) |
0(1(2(x))) | → | 2(0(1(x))) |
2(2(2(2(2(2(2(1(1(1(1(2(x)))))))))))) | → | 2(1(2(2(0(1(2(1(1(0(1(0(x)))))))))))) |
a | : | 1 → 1 |
b | : | 1 → 1 |
c | : | 1 → 1 |
0 | : | 0 → 0 |
1 | : | 0 → 0 |
2 | : | 0 → 0 |
0(1(2(x))) | → | 2(0(1(x))) |
2(2(2(2(2(2(2(1(1(1(1(2(x)))))))))))) | → | 2(1(2(2(0(1(2(1(1(0(1(0(x)))))))))))) |
t0 | = | 0(1(2(2(2(2(2(2(2(1(1(1(1(2(x270)))))))))))))) |
→1.1 | 0(1(2(1(2(2(0(1(2(1(1(0(1(0(x270)))))))))))))) | |
→1.1.1.1.1.1 | 0(1(2(1(2(2(2(0(1(1(1(0(1(0(x270)))))))))))))) | |
→ε | 2(0(1(1(2(2(2(0(1(1(1(0(1(0(x270)))))))))))))) | |
= | t3 |
t0 | = | 0(1(2(2(2(2(2(2(2(1(1(1(1(2(x270)))))))))))))) |
→ε | 2(0(1(2(2(2(2(2(2(1(1(1(1(2(x270)))))))))))))) | |
→1 | 2(2(0(1(2(2(2(2(2(1(1(1(1(2(x270)))))))))))))) | |
→1.1 | 2(2(2(0(1(2(2(2(2(1(1(1(1(2(x270)))))))))))))) | |
→1.1.1 | 2(2(2(2(0(1(2(2(2(1(1(1(1(2(x270)))))))))))))) | |
→1.1.1.1 | 2(2(2(2(2(0(1(2(2(1(1(1(1(2(x270)))))))))))))) | |
→1.1.1.1.1 | 2(2(2(2(2(2(0(1(2(1(1(1(1(2(x270)))))))))))))) | |
→1.1.1.1.1.1 | 2(2(2(2(2(2(2(0(1(1(1(1(1(2(x270)))))))))))))) | |
= | t7 |
csi