YES Confluence Proof

Confluence Proof

by Hakusan

Input

The rewrite relation of the following TRS is considered.

f(g(x)) f(h(x,x))
g(a) g(g(a))
h(a,a) g(g(a))

Proof

1 Compositional Parallel Critical Pair Systems

All parallel critical pairs of the TRS R are joinable by R. This can be seen as follows: The parallel critical pairs can be joined as follows. Here, ↔ is always chosen as an appropriate rewrite relation which is automatically inferred by the certifier.
The TRS C is chosen as:

There are no rules.

Consequently, PCPS(R,C) is included in the following TRS P where steps are used to show that certain pairs are C-convertible.
f(g(a)) f(g(g(a)))
f(g(a)) f(h(a,a))

Relative termination of P / R is proven as follows.

1.1 Rule Removal

Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1 over the naturals
[g(x1)] =
2 0 0
0 0 0
0 1 0
· x1 +
0 0 0
0 0 0
0 0 0
[h(x1, x2)] =
1 0 0
0 0 0
0 0 0
· x1 +
1 0 0
0 0 0
0 1 0
· x2 +
0 0 0
0 0 0
0 0 0
[a] =
0 0 0
1 0 0
0 0 0
[f(x1)] =
1 0 1
0 0 0
0 0 0
· x1 +
0 0 0
2 0 0
0 0 0
the rule
f(g(a)) f(h(a,a))
remains in R. Moreover, the rules
f(g(x)) f(h(x,x))
g(a) g(g(a))
h(a,a) g(g(a))
remain in S.

1.1.1 Rule Removal

Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1 over the naturals
[g(x1)] =
1 0 0
2 0 0
1 1 0
· x1 +
0 0 0
0 0 0
0 0 0
[h(x1, x2)] =
2 2 0
0 0 0
0 0 0
· x1 +
1 0 0
2 0 0
0 0 0
· x2 +
0 0 0
0 0 0
0 0 0
[a] =
0 0 0
1 0 0
0 0 0
[f(x1)] =
1 0 2
0 1 1
0 0 1
· x1 +
0 0 0
2 0 0
0 0 0
the rule
f(g(a)) f(h(a,a))
remains in R. Moreover, the rules
f(g(x)) f(h(x,x))
g(a) g(g(a))
remain in S.

1.1.1.1 Rule Removal

Using the linear polynomial interpretation over (2 x 2)-matrices with strict dimension 1 over the naturals
[g(x1)] =
2 0
0 1
· x1 +
0 0
0 0
[h(x1, x2)] =
1 0
0 0
· x1 +
1 0
0 0
· x2 +
0 0
0 0
[a] =
0 0
1 0
[f(x1)] =
2 2
0 2
· x1 +
0 0
2 0
all rules of R could be removed. Moreover, the rules
f(g(x)) f(h(x,x))
g(a) g(g(a))
remain in S.

1.1.1.1.1 R is empty

There are no rules in the TRS R. Hence, R/S is relative terminating.


Confluence of C is proven as follows.

1.2 (Weakly) Orthogonal

Confluence is proven since the TRS is (weakly) orthogonal.

Tool configuration

Hakusan