YES

(VAR x y)
(RULES
  plus(x,s(y)) -> s(plus(x,y))
  plus(x,z()) -> x
)

(COMMENT
Termination is shown by EKBO with interpretations on natural numbers

  plus_A(x1,x2) = x1 + 2
  z_A = 1
  s_A(x1) = 1
  plus#_A(x1,x2) = x1 + x2
  z#_A = 0

weights

  w0 = 1
  w(plus) = 0
  w(z) = 1
  w(s) = 1

and precedence:

plus > s > z
)