YES

(VAR x)
(RULES
  sqrt(0()) -> 0()
  +(0(),0()) -> 0()
  sqrt(+(i(x),x)) -> 0()
  i(0()) -> 0()
)

(COMMENT
Termination is shown by EKBO with interpretations on natural numbers

  i_A(x1) = 1
  0_A = 1
  sqrt_A(x1) = 1
  +_A(x1,x2) = 1
  0#_A = 0
  +#_A(x1,x2) = x1 + x2

weights

  w0 = 1
  w(i) = 1
  w(0) = 1
  w(sqrt) = 1
  w(+) = 0

and precedence:

i > sqrt > + > 0
)